\(\int \frac {(a+b x)^{10} (A+B x)}{x^9} \, dx\) [156]

Optimal result

Integrand size = 16, antiderivative size = 216 \[ \int \frac {(a+b x)^{10} (A+B x)}{x^9} \, dx=-\frac {a^{10} A}{8 x^8}-\frac {a^9 (10 A b+a B)}{7 x^7}-\frac {5 a^8 b (9 A b+2 a B)}{6 x^6}-\frac {3 a^7 b^2 (8 A b+3 a B)}{x^5}-\frac {15 a^6 b^3 (7 A b+4 a B)}{2 x^4}-\frac {14 a^5 b^4 (6 A b+5 a B)}{x^3}-\frac {21 a^4 b^5 (5 A b+6 a B)}{x^2}-\frac {30 a^3 b^6 (4 A b+7 a B)}{x}+5 a b^8 (2 A b+9 a B) x+\frac {1}{2} b^9 (A b+10 a B) x^2+\frac {1}{3} b^{10} B x^3+15 a^2 b^7 (3 A b+8 a B) \log (x) \]

[Out]

-1/8*a^10*A/x^8-1/7*a^9*(10*A*b+B*a)/x^7-5/6*a^8*b*(9*A*b+2*B*a)/x^6-3*a^7*b^2*(8*A*b+3*B*a)/x^5-15/2*a^6*b^3*
(7*A*b+4*B*a)/x^4-14*a^5*b^4*(6*A*b+5*B*a)/x^3-21*a^4*b^5*(5*A*b+6*B*a)/x^2-30*a^3*b^6*(4*A*b+7*B*a)/x+5*a*b^8
*(2*A*b+9*B*a)*x+1/2*b^9*(A*b+10*B*a)*x^2+1/3*b^10*B*x^3+15*a^2*b^7*(3*A*b+8*B*a)*ln(x)

Rubi [A] (verified)

Time = 0.10 (sec) , antiderivative size = 216, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {77} \[ \int \frac {(a+b x)^{10} (A+B x)}{x^9} \, dx=-\frac {a^{10} A}{8 x^8}-\frac {a^9 (a B+10 A b)}{7 x^7}-\frac {5 a^8 b (2 a B+9 A b)}{6 x^6}-\frac {3 a^7 b^2 (3 a B+8 A b)}{x^5}-\frac {15 a^6 b^3 (4 a B+7 A b)}{2 x^4}-\frac {14 a^5 b^4 (5 a B+6 A b)}{x^3}-\frac {21 a^4 b^5 (6 a B+5 A b)}{x^2}-\frac {30 a^3 b^6 (7 a B+4 A b)}{x}+15 a^2 b^7 \log (x) (8 a B+3 A b)+\frac {1}{2} b^9 x^2 (10 a B+A b)+5 a b^8 x (9 a B+2 A b)+\frac {1}{3} b^{10} B x^3 \]

[In]

Int[((a + b*x)^10*(A + B*x))/x^9,x]

[Out]

-1/8*(a^10*A)/x^8 - (a^9*(10*A*b + a*B))/(7*x^7) - (5*a^8*b*(9*A*b + 2*a*B))/(6*x^6) - (3*a^7*b^2*(8*A*b + 3*a
*B))/x^5 - (15*a^6*b^3*(7*A*b + 4*a*B))/(2*x^4) - (14*a^5*b^4*(6*A*b + 5*a*B))/x^3 - (21*a^4*b^5*(5*A*b + 6*a*
B))/x^2 - (30*a^3*b^6*(4*A*b + 7*a*B))/x + 5*a*b^8*(2*A*b + 9*a*B)*x + (b^9*(A*b + 10*a*B)*x^2)/2 + (b^10*B*x^
3)/3 + 15*a^2*b^7*(3*A*b + 8*a*B)*Log[x]

Rule 77

Int[((d_.)*(x_))^(n_.)*((a_) + (b_.)*(x_))*((e_) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*
x)*(d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, d, e, f, n}, x] && IGtQ[p, 0] && (NeQ[n, -1] || EqQ[p, 1]) && N
eQ[b*e + a*f, 0] && ( !IntegerQ[n] || LtQ[9*p + 5*n, 0] || GeQ[n + p + 1, 0] || (GeQ[n + p + 2, 0] && Rational
Q[a, b, d, e, f])) && (NeQ[n + p + 3, 0] || EqQ[p, 1])

Rubi steps \begin{align*} \text {integral}& = \int \left (5 a b^8 (2 A b+9 a B)+\frac {a^{10} A}{x^9}+\frac {a^9 (10 A b+a B)}{x^8}+\frac {5 a^8 b (9 A b+2 a B)}{x^7}+\frac {15 a^7 b^2 (8 A b+3 a B)}{x^6}+\frac {30 a^6 b^3 (7 A b+4 a B)}{x^5}+\frac {42 a^5 b^4 (6 A b+5 a B)}{x^4}+\frac {42 a^4 b^5 (5 A b+6 a B)}{x^3}+\frac {30 a^3 b^6 (4 A b+7 a B)}{x^2}+\frac {15 a^2 b^7 (3 A b+8 a B)}{x}+b^9 (A b+10 a B) x+b^{10} B x^2\right ) \, dx \\ & = -\frac {a^{10} A}{8 x^8}-\frac {a^9 (10 A b+a B)}{7 x^7}-\frac {5 a^8 b (9 A b+2 a B)}{6 x^6}-\frac {3 a^7 b^2 (8 A b+3 a B)}{x^5}-\frac {15 a^6 b^3 (7 A b+4 a B)}{2 x^4}-\frac {14 a^5 b^4 (6 A b+5 a B)}{x^3}-\frac {21 a^4 b^5 (5 A b+6 a B)}{x^2}-\frac {30 a^3 b^6 (4 A b+7 a B)}{x}+5 a b^8 (2 A b+9 a B) x+\frac {1}{2} b^9 (A b+10 a B) x^2+\frac {1}{3} b^{10} B x^3+15 a^2 b^7 (3 A b+8 a B) \log (x) \\ \end{align*}

Mathematica [A] (verified)

Time = 0.06 (sec) , antiderivative size = 208, normalized size of antiderivative = 0.96 \[ \int \frac {(a+b x)^{10} (A+B x)}{x^9} \, dx=-\frac {120 a^3 A b^7}{x}+45 a^2 b^8 B x+5 a b^9 x (2 A+B x)-\frac {105 a^4 b^6 (A+2 B x)}{x^2}+\frac {1}{6} b^{10} x^2 (3 A+2 B x)-\frac {42 a^5 b^5 (2 A+3 B x)}{x^3}-\frac {35 a^6 b^4 (3 A+4 B x)}{2 x^4}-\frac {6 a^7 b^3 (4 A+5 B x)}{x^5}-\frac {3 a^8 b^2 (5 A+6 B x)}{2 x^6}-\frac {5 a^9 b (6 A+7 B x)}{21 x^7}-\frac {a^{10} (7 A+8 B x)}{56 x^8}+15 a^2 b^7 (3 A b+8 a B) \log (x) \]

[In]

Integrate[((a + b*x)^10*(A + B*x))/x^9,x]

[Out]

(-120*a^3*A*b^7)/x + 45*a^2*b^8*B*x + 5*a*b^9*x*(2*A + B*x) - (105*a^4*b^6*(A + 2*B*x))/x^2 + (b^10*x^2*(3*A +
2*B*x))/6 - (42*a^5*b^5*(2*A + 3*B*x))/x^3 - (35*a^6*b^4*(3*A + 4*B*x))/(2*x^4) - (6*a^7*b^3*(4*A + 5*B*x))/x
^5 - (3*a^8*b^2*(5*A + 6*B*x))/(2*x^6) - (5*a^9*b*(6*A + 7*B*x))/(21*x^7) - (a^10*(7*A + 8*B*x))/(56*x^8) + 15
*a^2*b^7*(3*A*b + 8*a*B)*Log[x]

Maple [A] (verified)

Time = 0.41 (sec) , antiderivative size = 210, normalized size of antiderivative = 0.97

method	result	size
default	\(\frac {b^{10} B \,x^{3}}{3}+\frac {A \,b^{10} x^{2}}{2}+5 B a \,b^{9} x^{2}+10 A a \,b^{9} x +45 B \,a^{2} b^{8} x +15 a^{2} b^{7} \left (3 A b +8 B a \right ) \ln \left (x \right )-\frac {5 a^{8} b \left (9 A b +2 B a \right )}{6 x^{6}}-\frac {a^{9} \left (10 A b +B a \right )}{7 x^{7}}-\frac {a^{10} A}{8 x^{8}}-\frac {14 a^{5} b^{4} \left (6 A b +5 B a \right )}{x^{3}}-\frac {30 a^{3} b^{6} \left (4 A b +7 B a \right )}{x}-\frac {21 a^{4} b^{5} \left (5 A b +6 B a \right )}{x^{2}}-\frac {15 a^{6} b^{3} \left (7 A b +4 B a \right )}{2 x^{4}}-\frac {3 a^{7} b^{2} \left (8 A b +3 B a \right )}{x^{5}}\)	\(210\)
risch	\(\frac {b^{10} B \,x^{3}}{3}+\frac {A \,b^{10} x^{2}}{2}+5 B a \,b^{9} x^{2}+10 A a \,b^{9} x +45 B \,a^{2} b^{8} x +\frac {\left (-120 a^{3} b^{7} A -210 a^{4} b^{6} B \right ) x^{7}+\left (-105 a^{4} b^{6} A -126 a^{5} b^{5} B \right ) x^{6}+\left (-84 a^{5} b^{5} A -70 a^{6} b^{4} B \right ) x^{5}+\left (-\frac {105}{2} a^{6} b^{4} A -30 a^{7} b^{3} B \right ) x^{4}+\left (-24 a^{7} b^{3} A -9 a^{8} b^{2} B \right ) x^{3}+\left (-\frac {15}{2} a^{8} b^{2} A -\frac {5}{3} a^{9} b B \right ) x^{2}+\left (-\frac {10}{7} a^{9} b A -\frac {1}{7} a^{10} B \right ) x -\frac {a^{10} A}{8}}{x^{8}}+45 A \ln \left (x \right ) a^{2} b^{8}+120 B \ln \left (x \right ) a^{3} b^{7}\)	\(233\)
norman	\(\frac {\left (\frac {1}{2} b^{10} A +5 a \,b^{9} B \right ) x^{10}+\left (-\frac {105}{2} a^{6} b^{4} A -30 a^{7} b^{3} B \right ) x^{4}+\left (-\frac {15}{2} a^{8} b^{2} A -\frac {5}{3} a^{9} b B \right ) x^{2}+\left (-\frac {10}{7} a^{9} b A -\frac {1}{7} a^{10} B \right ) x +\left (10 a \,b^{9} A +45 a^{2} b^{8} B \right ) x^{9}+\left (-120 a^{3} b^{7} A -210 a^{4} b^{6} B \right ) x^{7}+\left (-105 a^{4} b^{6} A -126 a^{5} b^{5} B \right ) x^{6}+\left (-84 a^{5} b^{5} A -70 a^{6} b^{4} B \right ) x^{5}+\left (-24 a^{7} b^{3} A -9 a^{8} b^{2} B \right ) x^{3}-\frac {a^{10} A}{8}+\frac {b^{10} B \,x^{11}}{3}}{x^{8}}+\left (45 a^{2} b^{8} A +120 a^{3} b^{7} B \right ) \ln \left (x \right )\)	\(235\)
parallelrisch	\(\frac {56 b^{10} B \,x^{11}+84 A \,b^{10} x^{10}+840 B a \,b^{9} x^{10}+7560 A \ln \left (x \right ) x^{8} a^{2} b^{8}+1680 a A \,b^{9} x^{9}+20160 B \ln \left (x \right ) x^{8} a^{3} b^{7}+7560 B \,a^{2} b^{8} x^{9}-20160 a^{3} A \,b^{7} x^{7}-35280 B \,a^{4} b^{6} x^{7}-17640 a^{4} A \,b^{6} x^{6}-21168 B \,a^{5} b^{5} x^{6}-14112 a^{5} A \,b^{5} x^{5}-11760 B \,a^{6} b^{4} x^{5}-8820 a^{6} A \,b^{4} x^{4}-5040 B \,a^{7} b^{3} x^{4}-4032 a^{7} A \,b^{3} x^{3}-1512 B \,a^{8} b^{2} x^{3}-1260 a^{8} A \,b^{2} x^{2}-280 B \,a^{9} b \,x^{2}-240 a^{9} A b x -24 a^{10} B x -21 a^{10} A}{168 x^{8}}\)	\(248\)

[In]

int((b*x+a)^10*(B*x+A)/x^9,x,method=_RETURNVERBOSE)

[Out]

1/3*b^10*B*x^3+1/2*A*b^10*x^2+5*B*a*b^9*x^2+10*A*a*b^9*x+45*B*a^2*b^8*x+15*a^2*b^7*(3*A*b+8*B*a)*ln(x)-5/6*a^8
*b*(9*A*b+2*B*a)/x^6-1/7*a^9*(10*A*b+B*a)/x^7-1/8*a^10*A/x^8-14*a^5*b^4*(6*A*b+5*B*a)/x^3-30*a^3*b^6*(4*A*b+7*
B*a)/x-21*a^4*b^5*(5*A*b+6*B*a)/x^2-15/2*a^6*b^3*(7*A*b+4*B*a)/x^4-3*a^7*b^2*(8*A*b+3*B*a)/x^5

Fricas [A] (verification not implemented)

none

Time = 0.22 (sec) , antiderivative size = 245, normalized size of antiderivative = 1.13 \[ \int \frac {(a+b x)^{10} (A+B x)}{x^9} \, dx=\frac {56 \, B b^{10} x^{11} - 21 \, A a^{10} + 84 \, {\left (10 \, B a b^{9} + A b^{10}\right )} x^{10} + 840 \, {\left (9 \, B a^{2} b^{8} + 2 \, A a b^{9}\right )} x^{9} + 2520 \, {\left (8 \, B a^{3} b^{7} + 3 \, A a^{2} b^{8}\right )} x^{8} \log \left (x\right ) - 5040 \, {\left (7 \, B a^{4} b^{6} + 4 \, A a^{3} b^{7}\right )} x^{7} - 3528 \, {\left (6 \, B a^{5} b^{5} + 5 \, A a^{4} b^{6}\right )} x^{6} - 2352 \, {\left (5 \, B a^{6} b^{4} + 6 \, A a^{5} b^{5}\right )} x^{5} - 1260 \, {\left (4 \, B a^{7} b^{3} + 7 \, A a^{6} b^{4}\right )} x^{4} - 504 \, {\left (3 \, B a^{8} b^{2} + 8 \, A a^{7} b^{3}\right )} x^{3} - 140 \, {\left (2 \, B a^{9} b + 9 \, A a^{8} b^{2}\right )} x^{2} - 24 \, {\left (B a^{10} + 10 \, A a^{9} b\right )} x}{168 \, x^{8}} \]

[In]

integrate((b*x+a)^10*(B*x+A)/x^9,x, algorithm="fricas")

[Out]

1/168*(56*B*b^10*x^11 - 21*A*a^10 + 84*(10*B*a*b^9 + A*b^10)*x^10 + 840*(9*B*a^2*b^8 + 2*A*a*b^9)*x^9 + 2520*(
8*B*a^3*b^7 + 3*A*a^2*b^8)*x^8*log(x) - 5040*(7*B*a^4*b^6 + 4*A*a^3*b^7)*x^7 - 3528*(6*B*a^5*b^5 + 5*A*a^4*b^6
)*x^6 - 2352*(5*B*a^6*b^4 + 6*A*a^5*b^5)*x^5 - 1260*(4*B*a^7*b^3 + 7*A*a^6*b^4)*x^4 - 504*(3*B*a^8*b^2 + 8*A*a
^7*b^3)*x^3 - 140*(2*B*a^9*b + 9*A*a^8*b^2)*x^2 - 24*(B*a^10 + 10*A*a^9*b)*x)/x^8

Sympy [A] (verification not implemented)

Time = 4.00 (sec) , antiderivative size = 252, normalized size of antiderivative = 1.17 \[ \int \frac {(a+b x)^{10} (A+B x)}{x^9} \, dx=\frac {B b^{10} x^{3}}{3} + 15 a^{2} b^{7} \cdot \left (3 A b + 8 B a\right ) \log {\left (x \right )} + x^{2} \left (\frac {A b^{10}}{2} + 5 B a b^{9}\right ) + x \left (10 A a b^{9} + 45 B a^{2} b^{8}\right ) + \frac {- 21 A a^{10} + x^{7} \left (- 20160 A a^{3} b^{7} - 35280 B a^{4} b^{6}\right ) + x^{6} \left (- 17640 A a^{4} b^{6} - 21168 B a^{5} b^{5}\right ) + x^{5} \left (- 14112 A a^{5} b^{5} - 11760 B a^{6} b^{4}\right ) + x^{4} \left (- 8820 A a^{6} b^{4} - 5040 B a^{7} b^{3}\right ) + x^{3} \left (- 4032 A a^{7} b^{3} - 1512 B a^{8} b^{2}\right ) + x^{2} \left (- 1260 A a^{8} b^{2} - 280 B a^{9} b\right ) + x \left (- 240 A a^{9} b - 24 B a^{10}\right )}{168 x^{8}} \]

[In]

integrate((b*x+a)**10*(B*x+A)/x**9,x)

[Out]

B*b**10*x**3/3 + 15*a**2*b**7*(3*A*b + 8*B*a)*log(x) + x**2*(A*b**10/2 + 5*B*a*b**9) + x*(10*A*a*b**9 + 45*B*a
**2*b**8) + (-21*A*a**10 + x**7*(-20160*A*a**3*b**7 - 35280*B*a**4*b**6) + x**6*(-17640*A*a**4*b**6 - 21168*B*
a**5*b**5) + x**5*(-14112*A*a**5*b**5 - 11760*B*a**6*b**4) + x**4*(-8820*A*a**6*b**4 - 5040*B*a**7*b**3) + x**
3*(-4032*A*a**7*b**3 - 1512*B*a**8*b**2) + x**2*(-1260*A*a**8*b**2 - 280*B*a**9*b) + x*(-240*A*a**9*b - 24*B*a
**10))/(168*x**8)

Maxima [A] (verification not implemented)

none

Time = 0.22 (sec) , antiderivative size = 241, normalized size of antiderivative = 1.12 \[ \int \frac {(a+b x)^{10} (A+B x)}{x^9} \, dx=\frac {1}{3} \, B b^{10} x^{3} + \frac {1}{2} \, {\left (10 \, B a b^{9} + A b^{10}\right )} x^{2} + 5 \, {\left (9 \, B a^{2} b^{8} + 2 \, A a b^{9}\right )} x + 15 \, {\left (8 \, B a^{3} b^{7} + 3 \, A a^{2} b^{8}\right )} \log \left (x\right ) - \frac {21 \, A a^{10} + 5040 \, {\left (7 \, B a^{4} b^{6} + 4 \, A a^{3} b^{7}\right )} x^{7} + 3528 \, {\left (6 \, B a^{5} b^{5} + 5 \, A a^{4} b^{6}\right )} x^{6} + 2352 \, {\left (5 \, B a^{6} b^{4} + 6 \, A a^{5} b^{5}\right )} x^{5} + 1260 \, {\left (4 \, B a^{7} b^{3} + 7 \, A a^{6} b^{4}\right )} x^{4} + 504 \, {\left (3 \, B a^{8} b^{2} + 8 \, A a^{7} b^{3}\right )} x^{3} + 140 \, {\left (2 \, B a^{9} b + 9 \, A a^{8} b^{2}\right )} x^{2} + 24 \, {\left (B a^{10} + 10 \, A a^{9} b\right )} x}{168 \, x^{8}} \]

[In]

integrate((b*x+a)^10*(B*x+A)/x^9,x, algorithm="maxima")

[Out]

1/3*B*b^10*x^3 + 1/2*(10*B*a*b^9 + A*b^10)*x^2 + 5*(9*B*a^2*b^8 + 2*A*a*b^9)*x + 15*(8*B*a^3*b^7 + 3*A*a^2*b^8
)*log(x) - 1/168*(21*A*a^10 + 5040*(7*B*a^4*b^6 + 4*A*a^3*b^7)*x^7 + 3528*(6*B*a^5*b^5 + 5*A*a^4*b^6)*x^6 + 23
52*(5*B*a^6*b^4 + 6*A*a^5*b^5)*x^5 + 1260*(4*B*a^7*b^3 + 7*A*a^6*b^4)*x^4 + 504*(3*B*a^8*b^2 + 8*A*a^7*b^3)*x^
3 + 140*(2*B*a^9*b + 9*A*a^8*b^2)*x^2 + 24*(B*a^10 + 10*A*a^9*b)*x)/x^8

Giac [A] (verification not implemented)

none

Time = 0.31 (sec) , antiderivative size = 241, normalized size of antiderivative = 1.12 \[ \int \frac {(a+b x)^{10} (A+B x)}{x^9} \, dx=\frac {1}{3} \, B b^{10} x^{3} + 5 \, B a b^{9} x^{2} + \frac {1}{2} \, A b^{10} x^{2} + 45 \, B a^{2} b^{8} x + 10 \, A a b^{9} x + 15 \, {\left (8 \, B a^{3} b^{7} + 3 \, A a^{2} b^{8}\right )} \log \left ({\left | x \right |}\right ) - \frac {21 \, A a^{10} + 5040 \, {\left (7 \, B a^{4} b^{6} + 4 \, A a^{3} b^{7}\right )} x^{7} + 3528 \, {\left (6 \, B a^{5} b^{5} + 5 \, A a^{4} b^{6}\right )} x^{6} + 2352 \, {\left (5 \, B a^{6} b^{4} + 6 \, A a^{5} b^{5}\right )} x^{5} + 1260 \, {\left (4 \, B a^{7} b^{3} + 7 \, A a^{6} b^{4}\right )} x^{4} + 504 \, {\left (3 \, B a^{8} b^{2} + 8 \, A a^{7} b^{3}\right )} x^{3} + 140 \, {\left (2 \, B a^{9} b + 9 \, A a^{8} b^{2}\right )} x^{2} + 24 \, {\left (B a^{10} + 10 \, A a^{9} b\right )} x}{168 \, x^{8}} \]

[In]

integrate((b*x+a)^10*(B*x+A)/x^9,x, algorithm="giac")

[Out]

1/3*B*b^10*x^3 + 5*B*a*b^9*x^2 + 1/2*A*b^10*x^2 + 45*B*a^2*b^8*x + 10*A*a*b^9*x + 15*(8*B*a^3*b^7 + 3*A*a^2*b^
8)*log(abs(x)) - 1/168*(21*A*a^10 + 5040*(7*B*a^4*b^6 + 4*A*a^3*b^7)*x^7 + 3528*(6*B*a^5*b^5 + 5*A*a^4*b^6)*x^
6 + 2352*(5*B*a^6*b^4 + 6*A*a^5*b^5)*x^5 + 1260*(4*B*a^7*b^3 + 7*A*a^6*b^4)*x^4 + 504*(3*B*a^8*b^2 + 8*A*a^7*b
^3)*x^3 + 140*(2*B*a^9*b + 9*A*a^8*b^2)*x^2 + 24*(B*a^10 + 10*A*a^9*b)*x)/x^8

Mupad [B] (verification not implemented)

Time = 0.09 (sec) , antiderivative size = 230, normalized size of antiderivative = 1.06 \[ \int \frac {(a+b x)^{10} (A+B x)}{x^9} \, dx=x^2\,\left (\frac {A\,b^{10}}{2}+5\,B\,a\,b^9\right )-\frac {x\,\left (\frac {B\,a^{10}}{7}+\frac {10\,A\,b\,a^9}{7}\right )+\frac {A\,a^{10}}{8}+x^2\,\left (\frac {5\,B\,a^9\,b}{3}+\frac {15\,A\,a^8\,b^2}{2}\right )+x^3\,\left (9\,B\,a^8\,b^2+24\,A\,a^7\,b^3\right )+x^4\,\left (30\,B\,a^7\,b^3+\frac {105\,A\,a^6\,b^4}{2}\right )+x^5\,\left (70\,B\,a^6\,b^4+84\,A\,a^5\,b^5\right )+x^6\,\left (126\,B\,a^5\,b^5+105\,A\,a^4\,b^6\right )+x^7\,\left (210\,B\,a^4\,b^6+120\,A\,a^3\,b^7\right )}{x^8}+\ln \left (x\right )\,\left (120\,B\,a^3\,b^7+45\,A\,a^2\,b^8\right )+\frac {B\,b^{10}\,x^3}{3}+5\,a\,b^8\,x\,\left (2\,A\,b+9\,B\,a\right ) \]

[In]

int(((A + B*x)*(a + b*x)^10)/x^9,x)

[Out]

x^2*((A*b^10)/2 + 5*B*a*b^9) - (x*((B*a^10)/7 + (10*A*a^9*b)/7) + (A*a^10)/8 + x^2*((15*A*a^8*b^2)/2 + (5*B*a^
9*b)/3) + x^3*(24*A*a^7*b^3 + 9*B*a^8*b^2) + x^4*((105*A*a^6*b^4)/2 + 30*B*a^7*b^3) + x^5*(84*A*a^5*b^5 + 70*B
*a^6*b^4) + x^6*(105*A*a^4*b^6 + 126*B*a^5*b^5) + x^7*(120*A*a^3*b^7 + 210*B*a^4*b^6))/x^8 + log(x)*(45*A*a^2*
b^8 + 120*B*a^3*b^7) + (B*b^10*x^3)/3 + 5*a*b^8*x*(2*A*b + 9*B*a)